Rileys Freaky Fridays

You need to finish the question my friend. There is no way to tell the height of the building without a reference to how high the brick is in the air.

Just remember your kinematics equations, and remember that motion in the x direction can be separated from the motion in the y direction. (don’t forget to separate your initial speed into x and y components, also)

first find the vertical velocity.
Vy=v*sin(theta)
Vy=15sin(25)
Vy=6.339m/s

then use the equasion of motion.
x(t)=x+vt+(1/2)at^2
x(3s)=0+(6.339)(3)+(1/2)(9.81)(3^2)
x(3s)=63m

Vx:
15* Cos( 25) =13.59 m/s

Vy:
15* Sin( 25)=6.339 m/s

tup=6.33927/9.8 = 0.64686 s
tdown = 0.64686 s “to level of building”

time to ground from top of building:
3-(2*0.64686) = 1.7063

vo = vy= - 6.339 m/s

h=vo*t+(1/2)*g*t^2

how tall is the building?
h=
6.339* 1.7063+(1/2)*(9.8)*1.7063^2 = 25.0824 meter

Edit: *******
Here’s the check:
v = 15 m/s
angle = 25 degrees
yo = 25.0824 m “height of building”

vx = v * Cos(a) = 13.5946 m/s
vy = v * Sin(a) = 6.33927 m/s

tup = Vy / 9.8 =0.646864686320505 s
h = yo + Vy * tup + 0.5 * g * tup ^ 2 = 27.1327 m

tdown = Sqr(2 * h / 9.8)= 2.3531449s

T = tup + tdown = 3.0000096 s ******